4x^2-5.3x=-3x+5

Solution for 4x^2-5.3x=-3x+5 equation:

4x^2-5.3x=-3x+5

We move all terms to the left:

4x^2-5.3x-(-3x+5)=0

We get rid of parentheses

4x^2-5.3x+3x-5=0

We add all the numbers together, and all the variables

4x^2-2.3x-5=0

a = 4; b = -2.3; c = -5;
Δ = b2-4ac
Δ = -2.32-4·4·(-5)
Δ = 85.29
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2.3)-\sqrt{85.29}}{2*4}=\frac{2.3-\sqrt{85.29}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2.3)+\sqrt{85.29}}{2*4}=\frac{2.3+\sqrt{85.29}}{8}
$